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The x-axis contains the base of an equilateral triangle RST. The origin is at S. Vertex T has coordinates (2h, 0) and the y-coordinate of R is g, with g > 0. The x-coordinate of R is
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@abb0t
@abb0t : Can you help, it's bugging me.
We have the side length of the equilateral triangle as 2h. Dividing it into two right triangles with the altitude to R as the shared leg, we can use the Pythagorean theorem to find the height. \[(2h)^{2}-h ^{2}=y^{2}\] Which can be solved to yield\[y=h \sqrt{3}\]
you mean y=h\[\sqrt{2}\]
answer choices: 0 h 2h
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\[(2h)^{2}=2^{2}h^{2}=4h^{2}\] So \[x=\sqrt{3h^{2}}\]
Or y instead of x, sorry.
thanks(:
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