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Mathematics 11 Online
OpenStudy (anonymous):

Divergence...

OpenStudy (anonymous):

I nedd some help with series converges/divergens If \[n^{-1/2}\] is divergent, is \[1/2*n^{-1/2}\] then also divergent?

OpenStudy (dan815):

yes

OpenStudy (anonymous):

Great...

OpenStudy (anonymous):

So if I multiply a constant on at divergent/convergent series, the series will stay divergent/convergent.

OpenStudy (dan815):

yeah

OpenStudy (dan815):

whats a constant gonna matter when something is going to infinity

OpenStudy (dan815):

think about it 1000000000000000000000000000000000/10 is still a huge number

OpenStudy (dan815):

then infinity divided by 10 is still infinity

OpenStudy (dan815):

infact infinity dividided by 100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 still infinity no matter how many 00s there are there still infiniity... unless there are an infinite 0s there

OpenStudy (anonymous):

Thank you. So when \[\sum_{n=1}^{∞}\frac{ n^3+\ln(n) }{ \sqrt{n^7+n^2} }\ge1/2*n^{-1/2}\] for n≥1, the series are divergent. Right?

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