Question

Anyone in geometry b please check my answers,. geometry b?

Answer 1

53. What is the equation of the circle with center (2, –5) that passes through the point (–2, 10)? (1 point)
(x – 2)2 + (y – (–5))2 = 25
(x – (–2))2 + (y – 10)2 = 241
(x – 2)2 + (y – (–5))2 = 241
(x – (–2))2 + (y – 10)2 = 25

Answer 2

(x – 2)2 + (y – (–5))2 = 241

If the center is on 2 and -5,
it is:
(x-2)² + (y-(-5)² = R²
(x-2)² +(y+5)² = R²

To discover the radius, just do the distance between (2, -5) [center] to (-2, 10).
You will have:
sqrt ( 4² + 15²) = sqrt241

So, R² = 241.
(x-2)² + (y+r)² = 241

Answer 3

y+5 in the last equation.

Answer 4

A(x – 2)2 + (y – (–5))2 = 25
B (x – (–2))2 + (y – 10)2 = 241
C (x – 2)2 + (y – (–5))2 = 241
D (x – (–2))2 + (y – 10)2 = 25

Which 1?

Answer 5

C