solve x-y+4z=4, 2x+3y-3z=1, 3x+2y-2z=-1 using matrices
so, I'd think "cramer's rule" in this case works quicker
so, setup the matrix, and get the Determinant of the 3x3 matrix
http://i1.ytimg.com/vi/PO4hpSyxH9g/mqdefault.jpg those there are the Determinants for each variable, the one in the picture is a 2x2 but the procedure is the same for a 3x3 or else the only thing for a 3x3 the Determinant is nested one level further below
$$ \left\lbrack \begin{matrix} 1 & -1 & 4 \\ 2 & 3 & -3 \\ 3 & 2 & -1 \\ \end{matrix} \right\rbrack \color{red}{ \begin{matrix} | & 4 \\ | & 1 \\ | & -1 \\ \end{matrix} }\\ D_x = \left\lbrack \begin{matrix} \color{red}{4} & -1 & 4 \\ \color{red}{1} & 3 & -3 \\ \color{red}{-1} & 2 & -1 \\ \end{matrix} \right\rbrack\\ D_y = \left\lbrack \begin{matrix} 1 & \color{red}{4} & 4 \\ 2 & \color{red}{1} & -3 \\ 3 & \color{red}{-1} & -1 \\ \end{matrix} \right\rbrack \\ D_z = \left\lbrack \begin{matrix} 1 & -1 & \color{red}{4} \\ 2 & 3 & \color{red}{1} \\ 3 & 2 & \color{red}{-1} \\ \end{matrix} \right\rbrack\\ \text{and your Determinant for the }\\ \text{denominator will be the Determinant for}\\ D = \left\lbrack \begin{matrix} 1 & -1 & 4 \\ 2 & 3 & -3 \\ 3 & 2 & -1 \\ \end{matrix} \right\rbrack $$
I'm still confused
ok @Mad_e13
do you know how to get a determinant?
I don't remember any of matrices because I had the flu when we learned it last year
well http://easycalculation.com/matrix/learn-matrix-determinant.php and http://www.youtube.com/watch?v=C4yNX4jjHsk let me know any clearing out :)
@Mad_e13
ok
I understand that. so is that final D the answer or do I keep going?
the 4th post from the top (not counting mine) the very last thing on there ^
to use Cramer's rule, once you get the Determinants for each variable, then the variable is $$ \cfrac{D_x}{D} = x\\ \cfrac{D_y}{D} = y\\ \cfrac{D_z}{D} = z\\ $$
it can get tedious, mainly arithmethic really, just gets long, to get the Determinants
but once you have them, you just put them on top the the Determinant for the 3x3 original matrix
I'm still a little confused but I will ask my teacher about it. thanks for being so patient with me.
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