A random sample of 139 forty-year-old men contains 26%smokers. Find the P-value for a test of the claim that thepercentage of forty year-old men that smoke is 22%
I can't find the right answer
isnt this:\[\dfrac{\hat p-p}{\sqrt{\large \frac{pq}{n}}}\]??
Yes buti don't know how to solve it
\[\dfrac{.26-.22}{\sqrt{\large \frac{.22~.78}{139}}}\] gives us a zscore to play with
hopefully i used the right phat and p
do you recall if we subtract the claim proportion, or the sample proportion?
i think we subtract the claim, in which case -.22 is the way to go
that gives us a test statistic of 1.14
the claim is: 22% of 40yr smoke therefore the counter claim is that: 22% do not smoke this is a two tailed test. so we double the results of a tail to get the P-value
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