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Chemistry 18 Online
OpenStudy (anonymous):

Mass-Mass Conversions Use the following reaction equation to answer questions 1 and 2. Make sure you balance it first! NaBr + Ca(OH)2 ----> CaBr2 + NaOH How many grams of NaBr are needed to produce 187 grams of CaBr2?

OpenStudy (anonymous):

Ok so I need the steps, basically someone to walk me through it, any takers?

OpenStudy (chmvijay):

can u balance it :) since Br are there on right so u add 2 Brr on the left

OpenStudy (anonymous):

uh not really sure how to balance it either

OpenStudy (chmvijay):

2NaBr + Ca(OH)2 ----> CaBr2 + 2NaOH

OpenStudy (chmvijay):

can u tell molecular weight of NaBr

OpenStudy (chmvijay):

now dont say i dont know :)

OpenStudy (anonymous):

since you already have the balanced equation, start with the given mass of CaBr2 divide this by the molecular weight of CaBr2... after doing so, you'd get the moles of CaBr2 which you will need to convert to moles of NaBr using the balanced equation.. since there are 2moles NaBr per mole of CaBr2... then multiply it to the molecular weight of NaBr.

OpenStudy (anonymous):

i kinda need someone to walk me through this

OpenStudy (anonymous):

like actually show me all the steps

OpenStudy (anonymous):

can you balance the equation?

OpenStudy (anonymous):

2NaBr + Ca(OH)2 ----> CaBr2 + 2NaOH

OpenStudy (anonymous):

yes.! you copied this from above.. havent you??? :)

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

now, observe that 2 moles of NaBr produce 1 mole of CaBr2

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i want you to find the molar mass of NaBr and CaBr2 use a periodic table .... can you do this ?

OpenStudy (anonymous):

yup one sec

OpenStudy (anonymous):

NaBr=102.89 CaBr2=199.89

OpenStudy (anonymous):

good! i.e. 1 mole NaBr has 102.89g weight and 1 mole CaBr2 has 199.89g weight.. follow this thing?

OpenStudy (anonymous):

follow what thing?

OpenStudy (anonymous):

i mean to say,, what i said you understood?

OpenStudy (anonymous):

yeah i have the molar masses now what?

OpenStudy (anonymous):

now, you can say that to get 199.89 grams of CaBr2, you need 2 * 102.89 grams of NaBr. i multiplied by 2 because 2 moles of NaBr are needed to produce 1 mole CaBr2..

OpenStudy (anonymous):

ok and then what?

OpenStudy (anonymous):

now, it's just unitary method. 199.89 grams of CaBr2 produced by 205.78 grams of NaBr then, 187 grams of CaBr2 produced by \[\frac{ 205.78 }{ 199.89 }\times 187\]

OpenStudy (anonymous):

the ans. will be the no. of grams of NaBr required to produce 187 grams of CaBr2

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

I got 192.51 grams

OpenStudy (anonymous):

I think so

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