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OpenStudy (anonymous):
need help plz:
simplify:8 times the square root of 63 x to the fifth power
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OpenStudy (anonymous):
Do you mean:
\[8\sqrt{63x^5} \ or\ 8(\sqrt{63x})^5\]
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Which one do you want? The first or the second?
OpenStudy (anonymous):
the first
OpenStudy (anonymous):
\[8\sqrt{63x^5} = 8\sqrt{9*7x^5} = 8*3\sqrt{7x^5} = 24\sqrt{7x^5}\]
\[=24\sqrt{7x*x^4} = ?\]
What do you think the next step will be?
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OpenStudy (anonymous):
making x^4 look like x*x*x*x
OpenStudy (anonymous):
Your goal is to get x^4 out of the square root? Can you do it as it is, or would it be easier to right x^4 as x^2*x^2?
OpenStudy (anonymous):
right x^4 as X^2*X^2
OpenStudy (anonymous):
So can you take something out of the square root now?
OpenStudy (anonymous):
we can take x^2 out
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OpenStudy (anonymous):
Bravo! You can get it out as x^4 is x^2*x^2 = (x^2)^2!! So what would you have?
OpenStudy (anonymous):
24*2the sqrt of 9*7x
OpenStudy (anonymous):
\[24x^2\sqrt{7x}\]
Do you want me to explain this?
OpenStudy (anonymous):
yes plz
OpenStudy (anonymous):
You can write
\[x^2*x^2 \ as \ (x^2)^2\]
Ok with that?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
So what would be the result of:
\[\sqrt{(x^2)^2}\] ?
OpenStudy (anonymous):
x^4
OpenStudy (anonymous):
Let's try something easier. What is the result of:
\[\sqrt{9}\]?
OpenStudy (anonymous):
The result will be a number, that when it's squared, it will produce the number 9. Which number is it?
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