For some integer q, every odd integer is of the form (A)q (B)q+ 1 (C) 2q (D) 2q+ 1
@dan815
D
same reasons 2q+1 if 2q/2 = remained = 0 then 2q+1 gives u remainder 1 therefore odd
2q makes sure the result will be even. By adding one to it, you make sure it will be odd
Can I get the basic conception here ?
Try with each option by putting up some random values . Answer would be D
Any number (even or odd) that is multiplied with 2 gives an even number as a result. Ok with that?
q+1, and q for all integers can be either odd or ever
If you multiply 4 with 2 you get 8 (even). If you multiply 11 with 2, you get 22 (even). Every number that is multiplied with 2 gives an even number (multiple of 2).
2q must be even as it is divisible by 2 2q+1 must be odd as its a number that is divisible by 2 + 1 therefore will have remainder of 1
will have a remainder of 1 when divided by 2*
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