Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (goformit100):

For some integer q, every odd integer is of the form (A)q (B)q+ 1 (C) 2q (D) 2q+ 1

OpenStudy (goformit100):

@dan815

OpenStudy (dan815):

D

OpenStudy (dan815):

same reasons 2q+1 if 2q/2 = remained = 0 then 2q+1 gives u remainder 1 therefore odd

OpenStudy (anonymous):

2q makes sure the result will be even. By adding one to it, you make sure it will be odd

OpenStudy (goformit100):

Can I get the basic conception here ?

OpenStudy (anonymous):

Try with each option by putting up some random values . Answer would be D

OpenStudy (anonymous):

Any number (even or odd) that is multiplied with 2 gives an even number as a result. Ok with that?

OpenStudy (dan815):

q+1, and q for all integers can be either odd or ever

OpenStudy (anonymous):

If you multiply 4 with 2 you get 8 (even). If you multiply 11 with 2, you get 22 (even). Every number that is multiplied with 2 gives an even number (multiple of 2).

OpenStudy (dan815):

2q must be even as it is divisible by 2 2q+1 must be odd as its a number that is divisible by 2 + 1 therefore will have remainder of 1

OpenStudy (dan815):

will have a remainder of 1 when divided by 2*

OpenStudy (dan815):

|dw:1371139361147:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!