What is the standard deviation of this data to the nearest one hundredth? 10 12, 8, 2
whats the mean?
8
subtract 8 from every data point .. whats the set we get?
2, 4, 0, -6
good, now square those values
How?
n^2 = n*n
Multiply each number with itself
the longest part is simply finding the sum of the squares of the differences from the mean ....
step 1; find the mean of the set step 2; subtract the mean from the set step 3; square the results step 4; find the mean of the squares (if its a population), or use n-1 for a sample the result of this is called variance. the sqrt(variance) equals standard deviation
Ok i'm confused on the last step
2, 4, 0, -6 ; square these values 2^2, 4^2, 0^2, (-6)^2 ; what do we get to work with?
4, 16, 0, -36
-6 * -6 = 36 the idea is to have all positive values now considering that the data set is a population, and not a sample of a population .... what is the mean of the squares?
14
then the variance is 14 standard deviation is the sqrt of variance soooo sqrt(14) = ??? rnd it as they desire
Ok thanks
suppose this was a sample from a given population .... such that the population had 32 data points. that mean of the squares would be refering to a sample (of size 4) of the population and we would need to divide by: 4-1 but thats just insight into a different question
How do you round 14 to the nearest hundreth then?
*one hundreth
what do you get as the sqrt(14) ?
14?
or 196?
\[\sqrt{14}=??\]
im assuming you know how to operate a calculator for this
if not, type: sqrt(14) into a google search
3.741?
yep, the "hundreths" spot is 2 decimals
so, 3.74 is fine
ok thanks
youre welcome
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