Find the coordinates of the vertices of the figure formed by: y> 1/4x + 3/4 y> -x + 7 y< 2/3x + 2 Select one: a. (–4, 0), (5, 4), (5, 2) b. (–3, 0), (5, 4 ), (5, 2) c. (–4, 0), (3, 4), (5, 2) d. (–3, 0), (3, 4), (5, 2)
@FutureMathProfessor please help
@ChillOut
Use = instead of "<" and ">" Then you can solve those equations in terms of y. Then set the equations equal to each other, (Equation 1 = equation 2, equation 2 = equation 3, equation 1 = equation 3). By doing this, you will find the intersection points.
Which in turn are the vertices.
thanks
No problem.
So, what is the answer?
I think it is b
Am I right
\[1)\ \ \frac{1}{4}x + \frac{3}{4} = -x + 7 \rightarrow x = 5,\ y=2\ \ ||\ (5,2)\] \[2)\ \ -x + 7 =\frac{2}{3}x + 2 \rightarrow x =3,\ y=4\ ||\ (3,4)\] \[3)\ \ \frac{1}{4}x + \frac{3}{4} = \frac{2}{3}x + 2 \rightarrow x = -3,\ \ y=0\ \ ||\ (-3,0)\] Answer is d)
@jazzyfa30
yes I see where I mest up at
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