Question

need help simplifying part of this integral.

Answer 1

\[x\left[ \frac{ 1 }{ 11 }\tan(11x)-x \right]_{0}^{\pi/33}\]

Answer 2

\[\frac{ \pi }{ 33 }\left[ \frac{ 1 }{ 11 }\tan(\frac{ \pi }{ 3 })-\frac{ \pi }{33 } \right]\]

Answer 3

but if I distribute that, I dont know how to get the last term -pi^2/1089 to match the form the answer key gives me.

Answer 4

wouldnt the second term become 0

Answer 5

\[\frac{ -\pi(\pi-3\sqrt{3}) }{ 1089 }\]

Answer 6

show me the way!

Answer 7

\(x\left[ \frac{ 1 }{ 11 }\tan(11x)-x \right]_{0}^{\pi/33}\)

\(\pi/33\left[ \frac{ 1 }{ 11 }\tan(11 \pi/33)- \pi/33 \right] - 0 ( ... ) \)

Answer 8

oh that 2nd term, yes

Answer 9

I guess I only need help dealing with the first term.

Answer 10

yea i see let me think i overlooked the q a bit

Answer 11

sure, ill be here trying too :)

Answer 12

\[\frac{ \sqrt{3} \pi }{ 363 }-\frac{ \pi^2 }{ 1089 }\]

Answer 13

looks u nailed it :)

Answer 14

well not exactly.

i need it in the form above like 4 posts

Answer 15

if i multiply the first by 3 for a common denominator... i dont know how to get the result into the form I can use.

Answer 16

looks im no use here, il pass...

Answer 17

\[\frac{ -\pi(\pi-3\sqrt{3}) }{ 1089 }\]

Answer 18

\[\frac{ \ 3 \sqrt{3} \pi }{ 1089 }-\frac{ \pi^2 }{ 1089 }\]

Answer 19

lol

Answer 20

damn... they factor out a negative pi.. sigh