Question

solve log32 x=-2/5

solve logx 9=-1/2

solve log1/2 32=x

Answer 1

log32 x=-2/5

means that

x = 32 ^ (-2/5)

can you continue?

Answer 2

yeah

Answer 3

so x=.25?

Answer 4

yes
1 / (32^0.2)^2 = 1 / 2^2 = 1/4 0r 0.25

Answer 5

ok thanks so much!

Answer 6

yw

Answer 7

so the second one 9=x^(-1/2) how do you get the answer?

Answer 8

9 = 1
---
x^(1/2)

x^(1/2) = 1/9

now square both sides

x = (1/9)^2

Answer 9

do you do the same thing for the third one?

Answer 10

to get rid of the log function use :

if loga b = x

then b = a^ x

or if you find this difficult to remember use :

if
log10 100 = 2

then 100 = 10^2

you now the last part is true so its a check that you have it right

Answer 11

for the third one
you get

(1/2)^x = 32

in this case take logs to the base e and use your calculator

ln (0.5)^x = ln 32

x* ln(0.5) = ln 32
x = ln32 / ln(0.5)

Answer 12

x=-5?