if d/dx = (f(2x^5))=6x^5 calculate f'(x)

Question

loser66 · Answer

$$\frac{d}{dx}=(f(2x^5))=6x^5$$I don't understand, please explain

mertsj · Answer

I don't know.  Have to ask the smart people.  @Phi

phi · Answer

any other clues ?

loser66 · Answer

@jim_thompson5910

jim_thompson5910 · Answer

d/dx[ f(2x^5) ] = f ' (2x^5) * d/dx[2x^5]

d/dx[ f(2x^5) ] = f ' (2x^5) * 10x^4

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d/dx[ f(2x^5) ] = 6x^5

f ' (2x^5) * 10x^4 = 6x^5

f ' (2x^5) = 6x^5/10x^4

f ' (2x^5) = (3/5)x

that's as far as I could get

anonymous · Answer

so the answer is (3/5)x?

jim_thompson5910 · Answer

well no because they want f ' (x)

jim_thompson5910 · Answer

but not sure what the function f ' (x) could be, something seems missing, but idk

anonymous · Answer

thanks

jim_thompson5910 · Answer

np, i would ask your teacher about it

phi · Answer

ok, that makes sense @jim_thompson5910 

how about a change of variables?
f ' (2x^5) = (3/5)x

let u= 2x^5   and x=  (u/2)^(1/5)
f'(u) = (3/5) (u/2)^(1/5)
or , renaming u to x
$$ f'(x)= \frac{3}{5} \sqrt[5]{\frac{x}{2}} $$

loser66 · Answer

I am with phi, then