find the mass of the bar [AB] if the density function is f(x,y)=x. coordinates: A(1,0) B(3,1) it has to be a double integral
could you clarify your question more? i'm confused
i have to make up a integral using the coordinates of the bar and the density. i dont't remember the formula for the mass of a bar using integrals.
are we looking to do a double integral here? volume / density = mass
yes
is this bar a cylinder? because we can just put our f(x,y) into cylindrical coordinates and then solve for mass
m=∫∫Dρ(x,y)dA D is the domain of the bar. i can't use it as a cylinder. i found the formula but i'm still a little bit confused. dA is i remember right is sqrt of x^2+y^2
\[\int\limits_{1}^{3}\int\limits_{0}^{1} x dy dx= \int\limits_{1}^{3} x dx =\frac{ 3^2 }{ 2 }-\frac{ 1^2 }{2}=\frac{ 9-1 }{ 2 }-\frac{ 8 }{2}=4\]
is this correct?
in rectangular coordinates i don't remember any x^2 +y^2 for my jacobian... but that may be because i never really answered questions in rectangular
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