Question

Kendra cuts a triangle out of a piece of paper. With a protractor, she measures one of the angles to be 58.3°. Then she uses a ruler to find that the length of the opposite side is 16.5 cm, and the length of one of the other sides is 18.3 cm. To the nearest tenth of a cm, how long is the third side of Kendra's triangle?
A. 13.6 cm
B. 18.1 cm
C. 15.1 cm
D. 18.3 cm

please help! I've done all I coud trying to solve this

Answer 1

looks like a law of sines problem, yes?

Answer 2

does the law of sines sound familiar?

Answer 3

since you posted that here'a another question, how are you suppose to find the third side, and is it the same steps to finding the answer this problem?

Answer 4

we can find all the angles and all the sides

Answer 5

\[\frac{\sin(53.8)}{16.5}=\frac{\sin(B)}{18.3}\]
\[\sin(B)=\frac{18.3\sin(53.8)}{16.5}\]
\[B=\arcsin(\frac{18.3\sin(53.8)}{16.5})\]

Answer 6

okay.. I think I see how to do this.

Answer 7

i get 63.51
http://www.wolframalpha.com/input/?i=arcsin%28 \frac{18.3\sin%2853.8%29}{16.5}%29

Answer 8

then you know the other angle, since they have to add up to 180
then use the law of sines again to find the remaining side

i don't think there is a snappier way to do this, hopefully you are studying law of sines now

Answer 9

Nope.. That's why for my last two years of high school I am never taking anything geometry related ever again! But I kinda see what's going on here

Answer 10

who knows, you might end up being a math teacher

Answer 11

Funny! That's very unlikely..

Answer 12

not to sound like an old guy, but you never know...

Answer 13

Whatever happens, happens, hey but thanks for the help man.