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Chemistry 8 Online
OpenStudy (anonymous):

PLEASE HELP!!! If you used the 2507.6 Cal you expend in energy in one day to heat 81 kg of water at 20.0 ̊ C, what is the final temperature in ̊ C the water would reach? (Specific heat of water = 1.00 cal/g ̊ C).

OpenStudy (chmvijay):

Q=MC(T2-T1) c=1 cal/g C T1=20°C m=81 kg T2=???= final temperature Q=2507.6 Cal can u solve now

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