Mathematics
7 Online
OpenStudy (anonymous):
Which of the following functions represents the following graph?
f(x) = – |x| + 2
f(x) = –x + 2
f(x) = –x2 + 2
f(x) = –x3 + 2
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OpenStudy (anonymous):
OpenStudy (luigi0210):
well it's a parabola..
ganeshie8 (ganeshie8):
and its facing downwards
OpenStudy (luigi0210):
|dw:1371189521909:dw|
OpenStudy (luigi0210):
or -x^3
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OpenStudy (anonymous):
sooo its c ? im a little confused.
ganeshie8 (ganeshie8):
good guess :) it has to be c ! oly c is quadratic in the options
OpenStudy (anonymous):
soo i was right ? yaee thankkss very muchooo ! (:
OpenStudy (anonymous):
What is the solution to the equation 7 3x ≈ 9 ?
x = 0.376
x = 0.295
x = –0.295
x = –0.376
OpenStudy (luigi0210):
:l
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OpenStudy (anonymous):
idk how to do it :(
OpenStudy (luigi0210):
is there a sign between the 7 and 3x?
ganeshie8 (ganeshie8):
is the 3x in exponent ?
OpenStudy (anonymous):
yesss.
ganeshie8 (ganeshie8):
take log both sides
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OpenStudy (luigi0210):
Do you know how to convert to logs? @Lesha
OpenStudy (anonymous):
nooooo :(. i did it in vhemistry but i never could figure it out.
ganeshie8 (ganeshie8):
its a simple thingy much simpler than the polynomial stuff uve been doing so far
OpenStudy (anonymous):
so is it lod7^3=2.53 and log 9 =0.95
ganeshie8 (ganeshie8):
\(\large 7^{3x} = 9\)
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ganeshie8 (ganeshie8):
\(\large 7^{3x} = 9\)
take log base7 both sides
\(\large \log_7 7^{3x} = \log_7 9\)
ganeshie8 (ganeshie8):
\(\large 7^{3x} = 9\)
take log base7 both sides
\(\large \log_7 7^{3x} = \log_7 9\)
\(\large 3x \log_7 7 = \log_7 9\)
ganeshie8 (ganeshie8):
\(\large 7^{3x} = 9\)
take log base7 both sides
\(\large \log_7 7^{3x} = \log_7 9\)
\(\large 3x \log_7 7 = \log_7 9\)
\(\large 3x = \log_7 9\)
ganeshie8 (ganeshie8):
do u knw how to use calculator and find log fo a number ?
OpenStudy (luigi0210):
couldn't we just use
\[\log_{7} 9=3x\]
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OpenStudy (luigi0210):
nvm I was late >.>
OpenStudy (anonymous):
ill try
ganeshie8 (ganeshie8):
\(\large 7^{3x} = 9\)
take log base7 both sides
\(\large \log_7 7^{3x} = \log_7 9\)
\(\large 3x \log_7 7 = \log_7 9\)
\(\large 3x = \log_7 9\)
\(\large 3x = \log_7 9\)
\(\large 3x = \frac{\log 9}{\log 7}\)
ganeshie8 (ganeshie8):
use ur calculator and find wats \(\log 9\)
ganeshie8 (ganeshie8):
use ur calculator and find wats \(\log 7\)
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ganeshie8 (ganeshie8):
divide
OpenStudy (anonymous):
ii did and i got 0.885
OpenStudy (luigi0210):
Haha, @ganeshie8 is a genius :P
ganeshie8 (ganeshie8):
lol , try again doesnt look correct
ganeshie8 (ganeshie8):
knw what, u did the division reverse
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ganeshie8 (ganeshie8):
check it once
OpenStudy (anonymous):
okk so so is it lod7=0.85 and log 9 =0.95 . am i right so far ?
ganeshie8 (ganeshie8):
yes, now take log 9 / log 7
ganeshie8 (ganeshie8):
0.95/0.85 = ?
OpenStudy (anonymous):
i got 1.11
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ganeshie8 (ganeshie8):
thats right, so
3x = 1.11
x = ?
OpenStudy (anonymous):
0.37
OpenStudy (anonymous):
thats the answer . thanksss veryy muchh (:
ganeshie8 (ganeshie8):
np :)
OpenStudy (luigi0210):
Another soul enlighten, way to go! @ganeshie8
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ganeshie8 (ganeshie8):
lol, Lesha amazes me shes in oly her highschool and does these nasty problems for Algebra honors !