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Mathematics 7 Online
OpenStudy (anonymous):

Which of the following functions represents the following graph? f(x) = – |x| + 2 f(x) = –x + 2 f(x) = –x2 + 2 f(x) = –x3 + 2

OpenStudy (anonymous):

OpenStudy (luigi0210):

well it's a parabola..

ganeshie8 (ganeshie8):

and its facing downwards

OpenStudy (luigi0210):

|dw:1371189521909:dw|

OpenStudy (luigi0210):

or -x^3

OpenStudy (anonymous):

sooo its c ? im a little confused.

ganeshie8 (ganeshie8):

good guess :) it has to be c ! oly c is quadratic in the options

OpenStudy (anonymous):

soo i was right ? yaee thankkss very muchooo ! (:

OpenStudy (anonymous):

What is the solution to the equation 7 3x ≈ 9 ? x = 0.376 x = 0.295 x = –0.295 x = –0.376

OpenStudy (luigi0210):

:l

OpenStudy (anonymous):

idk how to do it :(

OpenStudy (luigi0210):

is there a sign between the 7 and 3x?

ganeshie8 (ganeshie8):

is the 3x in exponent ?

OpenStudy (anonymous):

yesss.

ganeshie8 (ganeshie8):

take log both sides

OpenStudy (luigi0210):

Do you know how to convert to logs? @Lesha

OpenStudy (anonymous):

nooooo :(. i did it in vhemistry but i never could figure it out.

ganeshie8 (ganeshie8):

its a simple thingy much simpler than the polynomial stuff uve been doing so far

OpenStudy (anonymous):

so is it lod7^3=2.53 and log 9 =0.95

ganeshie8 (ganeshie8):

\(\large 7^{3x} = 9\)

ganeshie8 (ganeshie8):

\(\large 7^{3x} = 9\) take log base7 both sides \(\large \log_7 7^{3x} = \log_7 9\)

ganeshie8 (ganeshie8):

\(\large 7^{3x} = 9\) take log base7 both sides \(\large \log_7 7^{3x} = \log_7 9\) \(\large 3x \log_7 7 = \log_7 9\)

ganeshie8 (ganeshie8):

\(\large 7^{3x} = 9\) take log base7 both sides \(\large \log_7 7^{3x} = \log_7 9\) \(\large 3x \log_7 7 = \log_7 9\) \(\large 3x = \log_7 9\)

ganeshie8 (ganeshie8):

do u knw how to use calculator and find log fo a number ?

OpenStudy (luigi0210):

couldn't we just use \[\log_{7} 9=3x\]

OpenStudy (luigi0210):

nvm I was late >.>

OpenStudy (anonymous):

ill try

ganeshie8 (ganeshie8):

\(\large 7^{3x} = 9\) take log base7 both sides \(\large \log_7 7^{3x} = \log_7 9\) \(\large 3x \log_7 7 = \log_7 9\) \(\large 3x = \log_7 9\) \(\large 3x = \log_7 9\) \(\large 3x = \frac{\log 9}{\log 7}\)

ganeshie8 (ganeshie8):

use ur calculator and find wats \(\log 9\)

ganeshie8 (ganeshie8):

use ur calculator and find wats \(\log 7\)

ganeshie8 (ganeshie8):

divide

OpenStudy (anonymous):

ii did and i got 0.885

OpenStudy (luigi0210):

Haha, @ganeshie8 is a genius :P

ganeshie8 (ganeshie8):

lol , try again doesnt look correct

ganeshie8 (ganeshie8):

knw what, u did the division reverse

ganeshie8 (ganeshie8):

check it once

OpenStudy (anonymous):

okk so so is it lod7=0.85 and log 9 =0.95 . am i right so far ?

ganeshie8 (ganeshie8):

yes, now take log 9 / log 7

ganeshie8 (ganeshie8):

0.95/0.85 = ?

OpenStudy (anonymous):

i got 1.11

ganeshie8 (ganeshie8):

thats right, so 3x = 1.11 x = ?

OpenStudy (anonymous):

0.37

OpenStudy (anonymous):

thats the answer . thanksss veryy muchh (:

ganeshie8 (ganeshie8):

np :)

OpenStudy (luigi0210):

Another soul enlighten, way to go! @ganeshie8

ganeshie8 (ganeshie8):

lol, Lesha amazes me shes in oly her highschool and does these nasty problems for Algebra honors !

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