Coulombs law describes the force of attraction or repulsion between electrically charged particles. If an electron is moved twice as far from the nucleus in an atom, how is the force of attraction affected?

Question

anonymous · Answer

$$F = \frac{ e*Ze}{ r ^{2} }  $$

this is how the coulomb's law should look like in an atom.
e is the charge on electron and Ze is the charge on the nucleus.

and as force is inversely proportional to the square of distance between the two point charges,
the force must become one fourth of it's initial value on doubling the distance between the two charges. i.e. on doubling r