Question

All the letters of the word ‘EAMCOT’ are arranged in different possible
ways. The number of such arrangements in which no two vowels are adjacent to each
other is
(A) 360 (B) 144 (C) 72 (D) 54

Answer 1

@dan815

Answer 2

@goformit100 this is NCERT question

Answer 3

http://www.ilslagos.com/db/homework/11/Ch_7%20Perm%5B1%5D.%20&%20Comb.pdf
go to example no. 15

Answer 4

E A M C O T
umm..do this
EAOMCT
group all the vowels together..
now subtract from total combinations :")
@yrelhan4 <3

Answer 5

(B) is the correct choice. We note that there are 3 consonants and 3
vowels E, A and O. Since no two vowels have to be together, the possible choice for
vowels are the places marked as ‘X’. X M X C X T X, these volwels can be arranged
in 4P3 ways 3 consonents can be arranged in 3 ways. Hence, the required number of
ways = 3! × 4P3
= 144

Answer 6

@yrelhan4 direct copy of my link!!

Answer 7

@goformit100

Answer 8

OOPS sorry there questions were from Science Olympiad, I didn't know it is from NCERT

Answer 9

oh!!!! its not your fault

Answer 10

Direct copy of ncert, i would say. i didnt even open your link..