solve the linear inequality 4-5/6x ≥ 7
\[\large \frac{4-5}{6x} \ge 7\] first off,what is 4-5?
\[4-\frac{ 5 }{ 6 }x \ge7\]
that is the problem that I need help to solve
Ohhh. okay. Misread it.
\[4-\frac{ 5 }{ 6x }\ge7=-\frac{ 5 }{ 6x}\ge7-4=\frac{ 5 }{6x }\le-3=5\le-18x =-\frac{ 5 }{ 18gex }\]
does it make a difference that it is \[\frac{ 5 }{ 6 }x \] and not \[\frac{ 5 }{ 6x }\]
\[\large 4-\frac{ 5 }{ 6 }x \ge7\] First we will subtract 4 on both sides. \[\large -4 + 4-\frac{ 5 }{ 6 }x \ge 7-4\] Simplify \[\large -\frac56 x \ge 3\] multiply both sides by the negative. And when you multiply or divide by a negative, you flip the sign. \[\large -(-\frac56 x) \le -3 \]simplify \[\large \frac56 x \le-3\]multiply by the reciprocal \[\large \frac65 \cdot \frac56 x \le -3\cdot \frac65\] simplify \[\large x \le \frac{-18}{5}\]
thank you
No problem, do you understand now?
yes I do
awesome :)
Join our real-time social learning platform and learn together with your friends!