Question

20L of nitrogen gas reacts with 100L of hydrogen gas to produce ammonia. What is the decrease in the volume of mixture?

Answer 1

convert the Volume to ML then subtract them.

Answer 2

the decrease in the volume of mixture is about 40.11L.

i am telling you the method.
do the calculations yourself, and ask if need help.

1) write balanced chemical reaction of reaction between N2 and H2 ok?
2) below the reactants, write their volume. (given in question)
3) calculate the number of moles of N2 and H2.
3.1) to calculate the number of moles, use unitary method. as in.
1 mole of gas occupies volume = 22.4L (definition of 1 mole)
then, x moles of gas occupies volume = 20L
CALCULATE X AND SIMILARLY, THE NUMBER OF MOLES OF H2.
4) see how many moles of N2 and H2 are reacting and how many moles of NH3 is produced.
5) convert this no.of moles into volume in the same way as converted volume into number of moles.
6) subtract the initial and final volumes.

i did this and answer came out to be 40.11L decrease in volume.


note. N2 is a limiting reagent here.
and some amount of H2 will remain unreacted. and you need to add it's volume too in the final volume. then only, you will get the correct result.

Answer 3

for the titration of 25.0mL of 0.20M hydroflouric acid with 0.20M NaOH, determine the volume of base added when pH is 2.85?

Answer 4

Thank you @anish95 ! :)

Answer 5

welcome! :-)