CAN SOMEONE PLLLZZZZ HELP!!!!!!!!!!!!
divide (2x/5y)/(x^2/25)

Question

CAN SOMEONE PLLLZZZZ HELP!!!!!!!!!!!!
divide (2x/5y)/(x^2/25)

whpalmer4 · Answer

$$\large{\frac{\frac{2x}{5y}}{\frac{x^2}{25}}}$$

You divide fractions by inverting the denominator fraction and multiplying it with the numerator fraction.  So this one becomes
$$\frac{2x}{5y}*\frac{25}{x^2} =$$

anonymous · Answer

everyone is saying (10)y/x but thats not the right anwer

whpalmer4 · Answer

And you can see that not only did @fernmndez violate the http://openstudy.com/code-of-conduct, they gave you an incorrect answer...

anonymous · Answer

would it become 50x/5yx^2

whpalmer4 · Answer

$$\frac{2x}{5y}*\frac{25}{x^2} = \frac{2*x*5*5}{5*y*x*x} = \frac{2*\cancel{x}*5*\cancel{5}}{\cancel{5}*y*x*\cancel{x}} = $$

anonymous · Answer

ok so it would be 10/yx

whpalmer4 · Answer

@ineedhelp72 Some would accept that, others would not.  I claim that you should either write 10/(yx) or learn how to typeset it as $$\frac{10}{yx}$$because it could also be interpreted as $$\frac{10}{y}*x$$ otherwise.

whpalmer4 · Answer

No point in getting the right answer if you can't clearly communicate it!