Question

For the quadratic function, finds it's vertex and line of symmetry, then graph the function.

3x^2 - 18x +32.

Answer 1

it vertex will be on its line of symmetry

Answer 2

given a quad of the form:

ax^2 + bx + c

the line of symmetry can be formulated as: x = -b/2a

by plugging value of x into the eqaution, we can solve for y

Answer 3

Ok I am stuck at this \[\frac{ 18 \pm \sqrt{-60} }{ 6}\] I know it will be \[3 \pm \sqrt{-60}\] but do I change that -60 to \[2\sqrt{5i}\] over 6?

Answer 4

Ok I guess what I'm asking is my vertex going to be \[3 + \frac{ 2\sqrt{5i} }{ 6 }, 3 - \frac{ 2\sqrt{5i} }{ 6 }\]

Answer 5

there are 2 parts to the formula you are trying to use.

there is the axis of symmetry part
and the distance from the axis