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Mathematics 7 Online
OpenStudy (anonymous):

Evaluate P(3, 0).

OpenStudy (mathstudent55):

Is there an equation?

OpenStudy (anonymous):

Im doing Probability and Statistics in math

OpenStudy (anonymous):

Like 7! over 8!6!

OpenStudy (uri):

I have also just started to learn Probability :o

OpenStudy (anonymous):

I hate probability it dosent sick in!

OpenStudy (uri):

No it's nice,I like it.

OpenStudy (mathstudent55):

You mean permutations? P(m, n) = m!/(m - n)!

OpenStudy (uri):

Questions like this i have just started : ^10P3 and ^7C4. @MKTY

OpenStudy (anonymous):

\[\bf P(3,0)=_{3}P _{0}=1\]

OpenStudy (anonymous):

It's just the number of permutations where as "C" would imply combinations.

OpenStudy (amistre64):

P(n,0) is defined as 1 since NOT picking anything is one option

OpenStudy (anonymous):

Ya permutations

OpenStudy (anonymous):

but what is P(3, 0), is it one?

OpenStudy (amistre64):

3!/3! ....

OpenStudy (anonymous):

1 ok

OpenStudy (anonymous):

So now what would C(10, 3) be?

OpenStudy (amistre64):

P(10,3) ------- 3!

OpenStudy (anonymous):

So C(10, 7)?

OpenStudy (amistre64):

consider the P to mean "pick" P(n,r) refers to starting at n, and picking r numbers: P(10,3) refers to: 10.9.8 3! can be thought of as P(3,3) if need be soo 10.9.8 ------- = C(10,3) 3.2.1

OpenStudy (amistre64):

10.9.8 ------ 3.2.1 10.9.8 ------ 3.2 10.3.8 ------ 2 10.3.4 = 10.12 = 120

OpenStudy (amistre64):

i find keeping it all factored helps to notice what parts can cancel or simplify out

OpenStudy (anonymous):

ya

OpenStudy (amistre64):

C(10,7) = P(10,7)/7! 10.9.8.7.6.5.4 -------------- 7.6.5.4.3.2.1 10.9.8 ------ 3.2.1 so C(10,7) is equal to C(10,3)

OpenStudy (anonymous):

Nice, I did it right and your examples made it easyer for me to do it next time thanks

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