Question

J= ∫x^2yds. it's a straight line with coordinates A(0,1) and B(3,2)

Answer 1

\[\int\limits_{[AB]} x^2y ds\]

Answer 2

ds refers to a distance integral:\[\sqrt{(x')^2+(y')^2}{}\]

Answer 3

might want to define your line as an equation tho

Answer 4

i used a formula for the equation of the line but.. i don't think that the formula that i've got is ok. i have to make it into a double integral?

Answer 5

the interval a to b defines "t"

x = 0+3t ; x^2 = 9t^2
y = 1 + t

Answer 6

x' = 3
y' = 1

Answer 7

\[\int_{0}^{1}9t^2(1+t)~\sqrt{3^2+1^2}~dt\]

Answer 8

thank you :)

Answer 9

yep