Omg i think the anwser is 9 but what is 6/2(1+2)=?
1 because 6/6 is 1.
6/2(1+2)=0 6/2(3)=0 6/6=0 The answer is 1
Dont YOU USe P.E.M.D.A.S i thought u do 1+2 then 6/2 then times 3 and 3 wich equals nine
If you are using PEMDAS it would be (1+2)=3 them multiplication so 3x2= 6 then division which is 6/6=1
PEMDAS 6/2(1+2) 6/2(3) 6/6 1 you multiply before you divide
left to right
the answer is 1 |dw:1371250464552:dw|
9
\[6/2(1+2)=6\times\frac{1}{2}\times(1+2)\]
It's 9, wrongy. Everyone above me is wrong, except Zarkon.
No because the "/" means division.
So how would you do it?
its the equivalent of saying \[6\div(2(1+2))\]
6/2(1+2) can be written as: \[\large \large \frac{ 6 }{ 2 } (1+2)\] Correct so far?
No. Following PEMDAS, you would first add 1 and 2 together to get 3. Then you would multiply 3 by 2 and get six. finally, you would divide 6 by 6 and get 1. Make sense?
The first step is right. You must do parenthesis first. So 1 + 2 is 3. Next, you have division or multiplication, right?
you do multiplication first. you can remember that by P-E-Multiplication-division-A-S
I guess you don't know what PEMDAS means.
PEMDAS = Parenthesis Exponent Multiplication/Division Division/Multiplication Addition/Subtraction Subtraction/Addition.
multiplication and division is done from left to right
What Zarkon said.
http://www.mathsisfun.com/operation-order-pemdas.html <-- Learn more about PEMDAS.
If division was first then is would be spelled PEDMAS
PEMDAS is just a way to help you...it does not give the full picture
...
What Zarkon said. Anyway, google PEMDAS. Everything will say Multiplication or division. (Whichever comes first from left to right)
http://www.wolframalpha.com/input/?i=6%2F%282%281%2B2%29%29 Here wolfram knows the answer
you didnt type it correctly.
type it as is
you will get 9
The input is wrong.
So it could go either way depending on where the parenthesis are?
\[\large \large \frac{ 6 }{ 2(1+2) } \neq \frac{ 6 }{ 2 } (1+2)\]
\[6/2(1+2)=6\div 2(1+2)=6\frac{1}{2}(1+2)\] it will always be 9
Another way of writing 6/2 (1+2) is: \[\large \large \frac{ 6 (1+2)}{ 2 } \ \] Does it make sense?
Ugh I feel bad that I gave her that answer then :(
she will live :)
@piercethesyd ik it was 9 i just wanted to make sure i was rite i got it rite but thnx
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