2/3y -5/4y +8= -11/12y-4
are we solving for y?
yes solving equations
\[\frac{ 2 }{ 3 }y - \frac{ 5 }{ 4 }y +8 = -\frac{ 11 }{ 12}y - 4\] is this the equation?
yes
okay so the first thing we want to do is get all those fractions to have the same least common denominator, which is 12 so now we get: \[\frac{ 8 }{12 }y - \frac{ 15 }{ 12 }y + 8 = -\frac{ 11 }{ 12}y - 4\]
oky
lets get all the y's on one side and subtract/add the coefficients
\[\frac{ 4 }{ 12 }y + 8 = -4\]
subtract both sides by 8 \[\frac{ 4 }{12 }y = -12\]
4/12 is actually 1/3 so \[\frac{ 1 }{ 3 }y = -12\]
what i have is 4/12 y + -3/12y + 11/12 -12
you changed your fractions wrong
oh ok one sec
2/3 ---> 8/12 5/4 ----> 15/12
y = -36
to get 8/12 did you multipy the 4 to 2/3?
yes, we want that 3 to become a 12, but we have to multiply the top by 4 also so 2*4 = 8 and 3*4 = 12.... so we get 8/12
okay what do i do with the + 8
just move it to the other side by subtracting 8 from both sides. look at my steps above, i already solved the entire problem
and do i subract 8 from -11/12
no, -11/12 is a coefficient of y, so you can only subtract it from -4
Join our real-time social learning platform and learn together with your friends!