Question

Determine the equation of the tangent to f(x)=x+sinx at x= pi

Answer 1

\[\huge f'(x)=1+cosx\]

Answer 2

f'(x) = m

Answer 3

now plug in x=pi into the x-value

Answer 4

yeah.. now put in x=pi.. that would give you the slope.

Answer 5

y= 180

Answer 6

\[\large f'(\pi )= 1 + \cos(\pi) = 0\]

Answer 7

m=0

Answer 8

because cos(pi) = -1.

Answer 9

you won, madame. :)

Answer 10

y=180 would be the equation ?

Answer 11

so the equation...we have m= 0, and can figure out our "b" value by plugging everything we know into

To figure out the "y" value, plug x=pi back into original equation.
\[\large y=f(\pi) = \pi + \sin(\pi)\] what is your y-value?

Answer 12

y=180

Answer 13

-_- y = pi.

now we have m =0, y = pi, x= pi.

\[y-y_{1}= m(x-x_{1})\]\[y-\pi = 0(x-\pi)\]\[y=\pi\]

Answer 14

No .. we can substitute pi for 180 @Jhannybean

Answer 15

You get the same thing :P