Find the point on the terminal side of θ = -3pi/4 that has an x coordinate of -1.
terminal side of what ??
I assume the equation itself.
Okay, so \((-1,Something)\) is at \(-3\pi/4\). 1) Where is \(-3\pi/4\)? What quadrant is it in? 2) What is the reference angle there? 3) You've a Pythagorean theorem to help you the rest of the way.
It's in the second quadrant. Reference angle?
Are you sure you have the background to solve this problem? It's in the 3rd quadrant. \(+3\pi/4\) is in the 2nd quadrant. It is not encouraging that you don't know what a reference angle is. You will need that information. Draw a ray from the origin in the direction of \(\3\pi/4\). What angle does this ray make with the x-axis?
Gotcha because it is negative. Well below the 3pi/4 is 225 degrees? This is from the unit circle.
@tanjeetsarkar96 Are you just guessing? You had it right before, but please do not just post answers.
Kind of. It's really -135º, but this gest you to the same place as +225º. Good work. Now the reference angle.
Well the answer does make since now that I think about it. Since the unit circle is only 1 digit for the x axis and the y axis, going to the very edge would force the y corrdinate to be 0. Is this the correct reasoning?
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