An experiment is conducted to investigate the kinetics of reaction between bromopropane and 0.1 moldm^-3 of sodium hydroxide. The rate equation is as follows: Rate = K[bromopropane][oh-]. The half-life of bromopropane in one of the experiments is T minutes. What is the new half life(in minutes) of bromopropane when the concentration of bromopropane is doubled and concentration of sodium hydroxide is reduced to 0.01 moldm^-3 ?
stuck at this question for a long time =( would appreciate any help given.
this is indeed a tricky one. this will take time.
are you sure that this ques. has nothing misssing?? or nothing incorrect?? i am just asking...
no there is nothing, it is a preliminary question from one of my schools here... dam its tough
i can give you options, gimme a min
yup .... it is.. tough... i am trying.. i am hoping to get the answer...
A .0.05 T B. 0.1T C. 5T D. 10T
it's night time.... and i must go now. i will try this ques. tomorrow.. i m going right now. this ques. is really very .. difficult.
for the second scenario in which A + B → P, the half-life of the reaction cannot be determined! because ln[B][A]o[A][B]o=k([B]o−[A]o)t
it can =/
i roughly know that u musnt take into account the changes occuring to bromoproapne because we are only concern with the half life of bromopropane and not the overall reaction
but the problem is i dont know how to go about doing it
i thought about that it is a second order reaction that the reactants are not the same. and we do not know anything about the initial concentration of bromopropane.
yes it is a second order reaction, but it is first order with respect to bromopropane
so concentration of bromopropane against time would result in having a constant half life
this goes for oh- too
it is only second order overall reaction
but i think that the half lives are dependent on each other.
i get what u mean.. but thats what i've been learning so far =(
if its first order with respect to a concentration.. u will get a constant half life
It is SN2 reaction. it has only one step. it is second order most of the times.
yes but reaction is first order with respect to bromopropane, thus plotting [bromopropane] against time will give u a constant half life, but if u plot [bromopropane][Oh-] against time, u will not get a constant half life
its only second order overall reaction, now we r only concern with a single reactant, not both
is it true that you look at the components separately?
yes, i believe we have to.. O.O
:) where did you get this question? can I see your source?
Im from singapore =/, the source is from National junior College preliminary examination 2012
dont worry, i double check the qn and made sure i wrote it all down correctly
do you have the answer of this ques??? is it 10T??
yes it is 10T =D teach me pls!
i put 5T as my answer...
wait for some time ,.. i am solving a ques. as soon as i am done withi this one, i will tell you how i arrived at the sol. PS. i don't know it is right or not.
ok!
this formula helped me..
AND THIS ONE TOO
NOW, WHAT I DID WAS, USED THE FORMULA HIGHLIGHTED IN GREY. AND CALCULATED THE HALF LIFE IN TWO CASES. CASE 1 : WHEN BROMOPROPANE AND NaOH ARE SAY... X AND 0.1 CASE 2: WHEN BROMOPROPANE AND NaOH ARE 2X AND 0.01 CALCULATED THE HALF LIFE IN HE TWO CASES......... ARE YOU FOLLOWING WHAT I AM SAYING???????????????????
ITS COMPLICATED.. I KNOW
how do u find the half life ? @.@
using the greyed formula
yes,,,
hmmm.... integrated rate law @.@
what happened???????? you type a message,,,, then erase it.... :) hard to comprehend?
its not in my syllabus! D=
yes.. absolutely... integrated rate law
????????????? wat?????????????????????? integrated rate law not in sylabus??
yes means i do not learn it XD, so they wanted to use what we've learnt from the simple rate equation to deduce the answer...
for half life, you need to know integrated rate law...
i learn the formula T1/2 = ln(2)/k
i think i will learn the rate law in university if i wish to carry on chemistry =/
integrated*
this is for the first order equation. and this one comes from the integrated rate law for first order equation. by putting the conc. at time t = 1/2 of the initial conc. yup u will.. but if u are asked this question of half life, then?
i manged to solve the question using T1/2 = ln(2)/ k[oh-] . so when [oh-] is divided by 10, t1/2= 10T relative to the initial experiment. But my tutor said it was wrong because that the equation i was using only applies to pseudo-zero order reaction
is it true its only for pseudo-zero? =/
yes,, your teacher is right in saying this.. you can't use first order equation to solve second order problem
T.T then i have no clue... because if i used that formula you gave me.. i wont finish the paper on time.. its a multiple choice question and we're only given 1.8 mins for each question T.T
anyway THX anish, at least i know how to derive the answer now
seeriously???????????????????????????????? i mean 1.8 mins for a question like this???
or.. how the answer was derived XD
:0
yes, we have 1.15 hours to finish 40 questions of multiple choices =(
welcome to.. singapore
where r u from anish? =)
:) that's not fair.. i think a question like this is in your paper just to kill your time.. i suppose..
i am from INDIA.
oooo! we had an exchange visit from india not long ago! =O
do u know of a school called CJC in short from india?
not sure which part though..
CHRIST JUNIOR COLLEGE?? ITS IN BANGALORE.... SOURCE -- GOOGLE :) https://www.google.co.in/#sclient=psy-ab&q=CJC+SCHOOL&oq=CJC+SCHOOL&gs_l=hp.3..0l2j0i22i30l2.2256.7239.0.10211.10.10.0.0.0.0.269.2165.2-10.10.0.ernk_timepromotionb..0.0...1.1.17.psy-ab.XbrrUcM5swg&pbx=1&bav=on.2,or.r_cp.r_qf.&bvm=bv.47883778,d.bmk&fp=9410b04d0e27bfd9&biw=1252&bih=527
yes! its christ junior college!
BUT I NEVER HEARD OF IT... :(
ohhh haha XD im from catholic junior college in singapore, in short for cjc too XD
you're in university alrdy? studying chemistry?
:-) i think that's precisely why they came there.. yes. i am pursuing my graduation in chemistry
yea haha XD chemistry as in theroretical chemitry?
i dunno what course to take for university and im 4 months away from my A levels @.@
well.......... take the subject in which you have interest...
true... haha XD. aight thx anish!
welcome... ezizio...!!
u from singapore na???
na?
delete the na.. :) u from singapore..?
oh haha yea i am XD
you've been here?
no.. not yet....
but someday........ i want to go and see places like singapore ...
now i can tell my friends that i have an international friend..::: an acquaintance from singapore..:P
o.o singapore is very small and boring XD but its a nice place to live in haha XD
:-P
lol! same here =D, but after my exams.. i have to serve national service for two years haha XD full time
national service???? millitary??
yea the military for two years =/
it's compulsory for all males...
isnt it..??
yea o.o you served yurs too?
dude.... this is awesome..... u know something?? i had always dreamt of joining army.... but due to poor eyesight, i am not eligible to go in army.. but in singapore, all males go to army,.... wish i was in singapore..:( no, i haven't served.... but i wanted to.:!
O.O i see =(, but 2 years is a long time =(...2 yearsof my life is wasted D=
no. no.. not wasted,,, its good.. its very good.. army.. discipline, good physique, u will learn to work in a team...for your country.. u know something..?? it is you who will be going to the army.. but i am feeling excited about it....:) strange,,, isnt it?
Join our real-time social learning platform and learn together with your friends!