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Chemistry 8 Online
OpenStudy (anonymous):

An experiment is conducted to investigate the kinetics of reaction between bromopropane and 0.1 moldm^-3 of sodium hydroxide. The rate equation is as follows: Rate = K[bromopropane][oh-]. The half-life of bromopropane in one of the experiments is T minutes. What is the new half life(in minutes) of bromopropane when the concentration of bromopropane is doubled and concentration of sodium hydroxide is reduced to 0.01 moldm^-3 ?

OpenStudy (anonymous):

stuck at this question for a long time =( would appreciate any help given.

OpenStudy (anonymous):

this is indeed a tricky one. this will take time.

OpenStudy (anonymous):

are you sure that this ques. has nothing misssing?? or nothing incorrect?? i am just asking...

OpenStudy (anonymous):

no there is nothing, it is a preliminary question from one of my schools here... dam its tough

OpenStudy (anonymous):

i can give you options, gimme a min

OpenStudy (anonymous):

yup .... it is.. tough... i am trying.. i am hoping to get the answer...

OpenStudy (anonymous):

A .0.05 T B. 0.1T C. 5T D. 10T

OpenStudy (anonymous):

it's night time.... and i must go now. i will try this ques. tomorrow.. i m going right now. this ques. is really very .. difficult.

OpenStudy (anonymous):

for the second scenario in which A + B → P, the half-life of the reaction cannot be determined! because ln[B][A]o[A][B]o=k([B]o−[A]o)t

OpenStudy (anonymous):

it can =/

OpenStudy (anonymous):

i roughly know that u musnt take into account the changes occuring to bromoproapne because we are only concern with the half life of bromopropane and not the overall reaction

OpenStudy (anonymous):

but the problem is i dont know how to go about doing it

OpenStudy (anonymous):

i thought about that it is a second order reaction that the reactants are not the same. and we do not know anything about the initial concentration of bromopropane.

OpenStudy (anonymous):

yes it is a second order reaction, but it is first order with respect to bromopropane

OpenStudy (anonymous):

so concentration of bromopropane against time would result in having a constant half life

OpenStudy (anonymous):

this goes for oh- too

OpenStudy (anonymous):

it is only second order overall reaction

OpenStudy (anonymous):

but i think that the half lives are dependent on each other.

OpenStudy (anonymous):

i get what u mean.. but thats what i've been learning so far =(

OpenStudy (anonymous):

if its first order with respect to a concentration.. u will get a constant half life

OpenStudy (anonymous):

It is SN2 reaction. it has only one step. it is second order most of the times.

OpenStudy (anonymous):

yes but reaction is first order with respect to bromopropane, thus plotting [bromopropane] against time will give u a constant half life, but if u plot [bromopropane][Oh-] against time, u will not get a constant half life

OpenStudy (anonymous):

its only second order overall reaction, now we r only concern with a single reactant, not both

OpenStudy (anonymous):

is it true that you look at the components separately?

OpenStudy (anonymous):

yes, i believe we have to.. O.O

OpenStudy (anonymous):

:) where did you get this question? can I see your source?

OpenStudy (anonymous):

Im from singapore =/, the source is from National junior College preliminary examination 2012

OpenStudy (anonymous):

dont worry, i double check the qn and made sure i wrote it all down correctly

OpenStudy (anonymous):

do you have the answer of this ques??? is it 10T??

OpenStudy (anonymous):

yes it is 10T =D teach me pls!

OpenStudy (anonymous):

i put 5T as my answer...

OpenStudy (anonymous):

wait for some time ,.. i am solving a ques. as soon as i am done withi this one, i will tell you how i arrived at the sol. PS. i don't know it is right or not.

OpenStudy (anonymous):

ok!

OpenStudy (anonymous):

this formula helped me..

OpenStudy (anonymous):

AND THIS ONE TOO

OpenStudy (anonymous):

NOW, WHAT I DID WAS, USED THE FORMULA HIGHLIGHTED IN GREY. AND CALCULATED THE HALF LIFE IN TWO CASES. CASE 1 : WHEN BROMOPROPANE AND NaOH ARE SAY... X AND 0.1 CASE 2: WHEN BROMOPROPANE AND NaOH ARE 2X AND 0.01 CALCULATED THE HALF LIFE IN HE TWO CASES......... ARE YOU FOLLOWING WHAT I AM SAYING???????????????????

OpenStudy (anonymous):

ITS COMPLICATED.. I KNOW

OpenStudy (anonymous):

how do u find the half life ? @.@

OpenStudy (anonymous):

using the greyed formula

OpenStudy (anonymous):

yes,,,

OpenStudy (anonymous):

hmmm.... integrated rate law @.@

OpenStudy (anonymous):

what happened???????? you type a message,,,, then erase it.... :) hard to comprehend?

OpenStudy (anonymous):

its not in my syllabus! D=

OpenStudy (anonymous):

yes.. absolutely... integrated rate law

OpenStudy (anonymous):

????????????? wat?????????????????????? integrated rate law not in sylabus??

OpenStudy (anonymous):

yes means i do not learn it XD, so they wanted to use what we've learnt from the simple rate equation to deduce the answer...

OpenStudy (anonymous):

for half life, you need to know integrated rate law...

OpenStudy (anonymous):

i learn the formula T1/2 = ln(2)/k

OpenStudy (anonymous):

i think i will learn the rate law in university if i wish to carry on chemistry =/

OpenStudy (anonymous):

integrated*

OpenStudy (anonymous):

this is for the first order equation. and this one comes from the integrated rate law for first order equation. by putting the conc. at time t = 1/2 of the initial conc. yup u will.. but if u are asked this question of half life, then?

OpenStudy (anonymous):

i manged to solve the question using T1/2 = ln(2)/ k[oh-] . so when [oh-] is divided by 10, t1/2= 10T relative to the initial experiment. But my tutor said it was wrong because that the equation i was using only applies to pseudo-zero order reaction

OpenStudy (anonymous):

is it true its only for pseudo-zero? =/

OpenStudy (anonymous):

yes,, your teacher is right in saying this.. you can't use first order equation to solve second order problem

OpenStudy (anonymous):

T.T then i have no clue... because if i used that formula you gave me.. i wont finish the paper on time.. its a multiple choice question and we're only given 1.8 mins for each question T.T

OpenStudy (anonymous):

anyway THX anish, at least i know how to derive the answer now

OpenStudy (anonymous):

seeriously???????????????????????????????? i mean 1.8 mins for a question like this???

OpenStudy (anonymous):

or.. how the answer was derived XD

OpenStudy (anonymous):

:0

OpenStudy (anonymous):

yes, we have 1.15 hours to finish 40 questions of multiple choices =(

OpenStudy (anonymous):

welcome to.. singapore

OpenStudy (anonymous):

where r u from anish? =)

OpenStudy (anonymous):

:) that's not fair.. i think a question like this is in your paper just to kill your time.. i suppose..

OpenStudy (anonymous):

i am from INDIA.

OpenStudy (anonymous):

oooo! we had an exchange visit from india not long ago! =O

OpenStudy (anonymous):

do u know of a school called CJC in short from india?

OpenStudy (anonymous):

not sure which part though..

OpenStudy (anonymous):

yes! its christ junior college!

OpenStudy (anonymous):

BUT I NEVER HEARD OF IT... :(

OpenStudy (anonymous):

ohhh haha XD im from catholic junior college in singapore, in short for cjc too XD

OpenStudy (anonymous):

you're in university alrdy? studying chemistry?

OpenStudy (anonymous):

:-) i think that's precisely why they came there.. yes. i am pursuing my graduation in chemistry

OpenStudy (anonymous):

yea haha XD chemistry as in theroretical chemitry?

OpenStudy (anonymous):

i dunno what course to take for university and im 4 months away from my A levels @.@

OpenStudy (anonymous):

well.......... take the subject in which you have interest...

OpenStudy (anonymous):

true... haha XD. aight thx anish!

OpenStudy (anonymous):

welcome... ezizio...!!

OpenStudy (anonymous):

u from singapore na???

OpenStudy (anonymous):

na?

OpenStudy (anonymous):

delete the na.. :) u from singapore..?

OpenStudy (anonymous):

oh haha yea i am XD

OpenStudy (anonymous):

you've been here?

OpenStudy (anonymous):

no.. not yet....

OpenStudy (anonymous):

but someday........ i want to go and see places like singapore ...

OpenStudy (anonymous):

now i can tell my friends that i have an international friend..::: an acquaintance from singapore..:P

OpenStudy (anonymous):

o.o singapore is very small and boring XD but its a nice place to live in haha XD

OpenStudy (anonymous):

:-P

OpenStudy (anonymous):

lol! same here =D, but after my exams.. i have to serve national service for two years haha XD full time

OpenStudy (anonymous):

national service???? millitary??

OpenStudy (anonymous):

yea the military for two years =/

OpenStudy (anonymous):

it's compulsory for all males...

OpenStudy (anonymous):

isnt it..??

OpenStudy (anonymous):

yea o.o you served yurs too?

OpenStudy (anonymous):

dude.... this is awesome..... u know something?? i had always dreamt of joining army.... but due to poor eyesight, i am not eligible to go in army.. but in singapore, all males go to army,.... wish i was in singapore..:( no, i haven't served.... but i wanted to.:!

OpenStudy (anonymous):

O.O i see =(, but 2 years is a long time =(...2 yearsof my life is wasted D=

OpenStudy (anonymous):

no. no.. not wasted,,, its good.. its very good.. army.. discipline, good physique, u will learn to work in a team...for your country.. u know something..?? it is you who will be going to the army.. but i am feeling excited about it....:) strange,,, isnt it?

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