Question

Solve and determine if a solution is extraneous.
Can someone please explain.Thanks! In progress...

Answer 1

\[\sqrt{x+16}+\sqrt{x=8}\]

Answer 2

I think that is probably \[\sqrt{x+16} + \sqrt{x} = 8\]Correct?

Answer 3

yes correct sorry

Answer 4

so solve for x we could square each side.

Answer 5

yes that i kind of understand after squared then what?

Answer 6

\[\left( \sqrt{x+16}+\sqrt{x=8}\right)^2\]

Answer 7

I am not sure whether I am right or wrong, just try. watch me, please
let x = a^2 . I try to form the form of |a +4i| = sqrt (a^2 +4^2|
and the second one is sqrt(a^2) = |a|

Answer 8

then |a+4i|+|a|= 8 solve for a, plug back to solve for x

Answer 9

\[\large \sqrt{x+16} + \sqrt{x} = 8\] square both sides \[\large (\sqrt{x+16} + \sqrt{x})^2 = (8)^2\] expand \[\large (\sqrt{x+16} +\sqrt{x})(\sqrt{x+16}+\sqrt{x}) = 64\]