Okay so: Amir pitched a baseball at an initial height of 5.9 feet with a velocity of 73.16 feet per second. About how long will it take the ball Amir pitched to hit the ground? 4.66 secs 2.94 secs 2.35 secs 1.47 secs
Would you follow the factoring process or.... ?
...
No One?
factor away :)
Oh ok... Thanks :) also when you get the final product which will be in t = ? OR t = ? which one will it be?
initial velocity formula, which is what you'd be using for this \(\huge h = -16t^2+vt+h_o\) you'd be solving for "t", you have "v" and when the ball hits the ground h = 0 so, just solve the quadratic :)
just a plain quadratic formula matter
ohh and \(h_o = 5.9\)
Wait, but isn't (t) just the time in which the projectile will hit it's max point?
hmm, that's "t" at the parabola vertex point "t" at the ground level, would be when y =0
So..... \[0 = -16x^{2} + 73.16 + 5.9\]
\(0 = -16x^{2} + 73.16x + 5.9\)
Oh yes right lol, so that's what I would use and I would factor right?
yes, you'd get 2 values, one will be extraneous or won't apply, and that'd be it :)
YESH thank you so much :D
yw
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