Question

g(x)=sqrt x+2 ; x=-2,-2,2,7
@jim_thompson5910

Answer 1

so starting with x=-2
i would get g(-2)=sqrt-2+2
so it'd be g(-2)=sqrt0????????????

Answer 2

the square root of 0 is _____

Answer 3

0

Answer 4

I'm assuming the function is \[\large g(x) = \sqrt{x+2}\]

Answer 5

so (-2,0) is on the graph

Answer 6

yup

Answer 7

o

Answer 8

:)

Answer 9

would the domain be all real numbers too?

Answer 10

no

Answer 11

there are some numbers that will not work

Answer 12

in general, you cannot take the square root of a negative number to get a real number as an output

Answer 13

so if x+2 is negative, then it won't work

this means you have to make x+2 either 0 or positive

Answer 14

x>=-2 is the domain?

Answer 15

good

Answer 16

you can also see the domain when you graph (like you saw the range)

Answer 17

and the range would be y>=0

Answer 18

yep

Answer 19

ty!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 20

sure thing

Answer 21

how is the graph suppose to look?

Answer 22

something like that?

Answer 23

something like this