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Mathematics 17 Online
OpenStudy (anonymous):

Simplify: 1/x-1/x+2

OpenStudy (anonymous):

\[\frac{ 1 }{ x }-\frac{ 1 }{ x+2 }\]

OpenStudy (anonymous):

I got a common denominator and got this: 2/X^2+2x. Is that right?

OpenStudy (espex):

Not sure how you got the 2 on top, care to show your steps?

OpenStudy (anonymous):

\[\frac{ x+2 }{ x+2 }(\frac{ 1 }{ x })-(\frac{ 1 }{ x+2 })\frac{ x }{ x }\] \[\frac{ x+2 }{ x^2+2x }-\frac{ x }{ x^2+2x }\]

OpenStudy (anonymous):

\[\frac{ 2 }{ x^2+2x }\]

OpenStudy (espex):

Excellent work. :)

OpenStudy (anonymous):

So it's right?

OpenStudy (espex):

Yes. Good job.

OpenStudy (anonymous):

Thanks.

OpenStudy (espex):

You did the work, but you are welcome just the same. :D

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