When 3 coins are tossed, what is the probability of getting (i) 2 heads and a tail (ii) at least 2 tails
There are 8 possible outcomes when 3 fair coins are tossed: TTT TTH THT THH HTT HTH HHT HHH How many of the outcomes have 2 heads and a tail?
Notice that saying "probability of 2 heads and a tail" is the same as saying "the probability of 3 heads", since the chance of getting a tail or a heads is equal, i.e 1/2. Hence, to get the probability of 3 heads on 3 coins, it's just 1/2 x 1/2 x 1/2 = ?
If the binomial distribution is used to solve (i) the correct calculation is found as follows: \[P(2\ heads)=3C2\times 0.5^{2}\times 0.5=3C2\times 0.5^{3}\]
The answer for it is (i) 1/72 (ii) 1/54 but i do not know how to arrive at it
no it isn't two heads and a tail THH HTH HHT three out of eight
@amstro Are you sure that you have posted the question correctly. The answer that you have posted for (i) is definitely not correct for the question as posted.
@kropot72 i checked the question it is correct.
Then the answer that you posted is incorrect. The correct answer has been confirmed by @satellite73
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