Question

again differentiation.

Answer 1

try them yourself before posting.

Answer 2

\[\cot ^{-1}[ \left[ \sqrt{1+sinx}+\sqrt{1-sinx} \right]\div \left[ \sqrt{1+sinx}- \sqrt{1-sinx}\right]]\]

Answer 3

lol

Answer 4

m trying ..!! but dats tooo hard..

Answer 5

@satellite73 help me out.!

Answer 6

@genius12

Answer 7

i think we need to "simplify" the inside part a bit

Answer 8

just multiply the top and bottom of the fraction by the conjugate of the denominator to simplify things a bit. then apply chain rule and stuff with quotient rule and you're good.

Answer 9

try
\[\frac{\sqrt{1+x}-\sqrt{1-x}}{\sqrt{1+x}+\sqrt{1-x}}\] first

Answer 10

rationalize the denominator, and you will get
\[\frac{\sqrt{1-x^2}+1}{x}\]

Answer 11

dis wat it came after simplify .