A farmer has 140ft of fencing with which she will enclose a rectangular region adjacent to a barn 6ft long. If she insists on using the entire length of the barn as a portion of one side of the rectangle, what is the maximum area that may be enclosed?
so when is area greatest in a rectangle?
and from that, you know L x W = Area and you have worked out L and are given W so Area = ??? (square feet)
Hey, sorry I had to run to the store quick. Just reading what you said quickly
length= 64 and area=384
ahh.. close... try length again
I had a typo sorryl length is 67 and area is 402
sweet, spot on!
So maximum area is 402?
yep, if he insists on using the barn as a side
Is there a different way of solving it? Just so that I understand better
for that one, it's the only way of solving it as its the only area you can get as per picture, rectangle has 2 groups of 2 equal sides so as one side is marked as 6 ft long, the side opposite to that has to be the same length, which leaves only one variable to solve (Length)
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