Chemistry
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OpenStudy (anonymous):
how to solve empirical formula?
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OpenStudy (missmob):
i can help you
OpenStudy (missmob):
okay ill give you a example
OpenStudy (anonymous):
ok
OpenStudy (missmob):
take caffine for instance C6H10N4O2
OpenStudy (missmob):
wait its c8
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OpenStudy (missmob):
so its empherical formula will be C8H10N4O2=C4H5N2O
OpenStudy (missmob):
so did i help
OpenStudy (missmob):
??
OpenStudy (missmob):
hey did this help you
OpenStudy (anonymous):
can u show me how to work it out
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OpenStudy (missmob):
the half of 8 =4
OpenStudy (missmob):
O had 2 so we didnt write anything for it
OpenStudy (anonymous):
what about H10
OpenStudy (missmob):
the half of 10=5
OpenStudy (anonymous):
so we to do just half them
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OpenStudy (missmob):
and one more thing some times the empherical formula is the same as given
OpenStudy (missmob):
like C9H8O4 its empherical formula will be the same
OpenStudy (missmob):
because c9 cannot be simplified
OpenStudy (missmob):
so did it help
OpenStudy (anonymous):
why it can be half too
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OpenStudy (missmob):
no it cant
OpenStudy (missmob):
how can 9 be half u see
OpenStudy (missmob):
its not about half its about simplify
OpenStudy (anonymous):
ok
OpenStudy (missmob):
so please clear your doubts
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OpenStudy (missmob):
so did it help
OpenStudy (missmob):
hey wth