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Chemistry 18 Online
OpenStudy (anonymous):

how to solve empirical formula?

OpenStudy (missmob):

i can help you

OpenStudy (missmob):

okay ill give you a example

OpenStudy (anonymous):

ok

OpenStudy (missmob):

take caffine for instance C6H10N4O2

OpenStudy (missmob):

wait its c8

OpenStudy (missmob):

so its empherical formula will be C8H10N4O2=C4H5N2O

OpenStudy (missmob):

so did i help

OpenStudy (missmob):

??

OpenStudy (missmob):

hey did this help you

OpenStudy (anonymous):

can u show me how to work it out

OpenStudy (missmob):

the half of 8 =4

OpenStudy (missmob):

O had 2 so we didnt write anything for it

OpenStudy (anonymous):

what about H10

OpenStudy (missmob):

the half of 10=5

OpenStudy (anonymous):

so we to do just half them

OpenStudy (missmob):

and one more thing some times the empherical formula is the same as given

OpenStudy (missmob):

like C9H8O4 its empherical formula will be the same

OpenStudy (missmob):

because c9 cannot be simplified

OpenStudy (missmob):

so did it help

OpenStudy (anonymous):

why it can be half too

OpenStudy (missmob):

no it cant

OpenStudy (missmob):

how can 9 be half u see

OpenStudy (missmob):

its not about half its about simplify

OpenStudy (anonymous):

ok

OpenStudy (missmob):

so please clear your doubts

OpenStudy (missmob):

so did it help

thomaster (thomaster):

@sajidabatool \(\bf\Huge Welcome~to~\color{#00B4ff}{Open}\color{#7cc517}{Study}~!!!\) take a look at this explanation about empirical formulas http://openstudy.com/study#/updates/51b19f6ae4b05b167ed31cb6

OpenStudy (missmob):

hey wth

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