Question

Are the following algebraic expressions a POLYNOMIAL OR NOT?

1. (square root of ) x^3 y^2 z

2. 12ab^2
--------
5ab

3. -3
-------
xy

4. 9(cube root of z)

5. ((square root of 3) x^2 y^3) / 4xy^2

Answer 1

they r not, in the polinomila the exponents must be integers

Answer 2

^ positive integers

Answer 3

and the answer's wrong. I can see at least one expression, which, when simplified, becomes a polynomial.

Answer 4

@bahrom7893 what expression can be a polynomial?

Answer 5

Simplify each of them and post what you get.

Answer 6

@kaylala : polynomial is something which has power of an integer, not a fraction

Say x^2 is a polynomial , not x^2/3

I hope you got this one.

Answer 7

@bahrom7893

1. cant be simplified

2. 12b^2
---------
5

3. still the same

4. same

5. (square root of 3) xy
------------------
4




??????

Answer 8

well technically x^2/3 is a polynomial, x^(2/3) is not.

Answer 9

So once you have simplified it, which one ends up with positive integer exponents?

Answer 10

@bahrom7893 where did you get x^2/3?

Answer 11

nvm that, it was from an example that thinker was talking about. From your own simplified post. Which of those expressions have positive integer exponents?

Answer 12

so, what's the answer per number item?

Answer 13

I'm not going to give you the answer. You are 90% there. Can you just answer which of the expressions, when simplified end up with positive integer exponents? <- that expression will be your answer.

Answer 14

number 2?

Answer 15

yes

Answer 16

but # 2 has a denominator??

Answer 17

but not in the exponent

Answer 18

doesnt # 2 have a variable in the denominator? @bahrom7893

Answer 19

2. 12b^2
-------- where do you see a variable in the denominator?
5

Answer 20

ohhh..ok
so the variable hence is a letter.

is # 2 the only polynomial out of all?
@bahrom7893

Answer 21

yes. basically polynomials follow a form a*x^(n) where a can be any number, n has to be a positive integer.

Answer 22

ok. thanks @bahrom7893