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Use the properties of logarithms to evaluate
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\[\large2\log_7\sqrt[3]7\]
use\[\sqrt[n]x=x^{1/n}\]
and\[\boxed{n\log_b x=\log_bx^n}\]\[\boxed{\log_b b=1}\]
is the answer going to be a whole number or a fraction?
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the answer is a fraction the answer is 2/3
what answer are you getting @selenamalter?
\[2 * \log _{7}(7^{1/3)} = \frac{ 2 }{ 3 } \log _{7}(7) = 2/3\] as, \[\sqrt[3]{7} = 7^{(1/3)}\] and \[\log(x ^{n}) = n * \log(x)\]
and \[\log _{7}(7) = 1\]
okay, so i did it too and got 2/3
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