Prove that the product of any r consecutive numbers is divisible by r! .

Question

goformit100 · Answer

yes r factorial

anonymous · Answer

Well i'm not sure I know the answer to this question but maybe we can work together. I know that 5! is 1x2x2x4x5 so now we know that r! is.

anonymous · Answer

This is a physics question, isn't it?

anonymous · Answer

Here, http://www.physicsforums.com/showthread.php?t=176717 that could probably help you. c:

anonymous · Answer

Kirby, where'd you get 5?

anonymous · Answer

well.. it would have to be divisible by r!

if you have 5 consecutive numbers, lets say 10/11/12/13/14

then 5! = 5*4*3*2*1

you can notice 12 is divisible by 3*4, 10 by 5*2

anonymous · Answer

I see..

goformit100 · Answer

Ok

goformit100 · Answer

Thank you Sir

anonymous · Answer

well i typed out a fairly nice post showing exactly what I meant, but my comp froze and I lost it all

point was, for any length r, you will create a series of consecutive numbers such that r! is a factor in every one (except primes, of course)

because the values along your length r depend on r itself