Question

If 65.0 grams of Ca(OH)2 react with an excess of NaBr, how much NaOH is produced?

Answer 1

Here is some info you may need, NaBr+Ca(OH)2----------------->CaBr2+NaOH

Answer 2

first find moles of Ca(OH)2 in 0.65 grams=0.65/(40+(2(16+1))
by stoichiometry moles of Ca(OH)2=moles of NaOH
mass of NaOH= Moles x Mr

Answer 3

get it??

Answer 4

what's Mr?

Answer 5

Mr=molar mass=mass of 1 mole of a substance
for NaOH Mr=23+16+1
=40

Answer 6

how do I find moles of Ca(OH)2 in 0.65 grams?

Answer 7

moles=mass/Mr
=0.65/(74)
where 74 is Mr=40+2(16+1)
see my first post

Answer 8

ok but how do I find out how much NaOH is produced? still alil confused.....................

Answer 9

you have moles of Ca(OH)2?

Answer 10

i am confused

Answer 11

can we break it down again from the beginning?

Answer 12

Ok
Step 1
Find Mr of Ca(OH)2

Answer 13

Step 2
Find Moles of Ca(OH)2

Answer 14

Step 3
From equation Moles of NaOH=Moles of Ca(OH)2 (1:1 in the equation)

Answer 15

Step 4
Mass of NaOH=Moles (found in previous step) x Mr of NaOH

Answer 16

no it's actually 74.09= Mr of Ca(OH)2

Answer 17

no Mr of Ca(OH)2 =mass of Ca + 2(mass of O + mass of H)
=40+2(16+1)
=74.09

Answer 18

follow these steps and see if you can achieve the answer

Answer 19

Ok so for step 2, in order to find the moles I need to divide .65/74?

Answer 20

I get 0.878

Answer 21

that's right

Answer 22

and I multiply that by 39.997

Answer 23

I get 35.1325

Answer 24

yes and you will get your answer

Answer 25

so is my final answer 35.1325 grams of NaOH?

Answer 26

yes

Answer 27

ty!!!!!!!!!!!!!!!!!!!!!

Answer 28

:)

Answer 29

:)