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Physics 25 Online
OpenStudy (jaze):

The velocity vector of the boat has two components: v1 is the velocity of the water and v2 is the velocity of the boat relative to the water. If v1= 3 km/h and v2= 5 km/h, determine the velocity vector of the boat.

OpenStudy (jaze):

OpenStudy (anonymous):

what is the answer??

OpenStudy (jaze):

7.55 km/h @ 25.2 degrees

OpenStudy (anonymous):

ok so here are the steps first resolve the forces into components horizontal component of v2=5cos(40)=3.8 horizontal component of v1=v1 (as v1 is horizontal (angle=0)) total horizontal resultant=3.8+v1=6.8 vertical component of v2=5sin(40)=3.2 vertical component of v1=0 (angle=90) total vertical resultant=3.2 magnitude of velocity vector=sqrt(3.2^2+6.8^2) direction of velocity vector=tan inverse (3.2/6.8)

OpenStudy (jaze):

thank you so much!! :D

OpenStudy (anonymous):

np :)

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