Please help me solve the following problem. Where does the line x=1+3t , y=2-t intersect the parabola y=x^2?
first step is to convert the parametric form of the line into the standard form involving just x and y. i.e. eliminate 't' from the equations.
equation of the line: \[y=-\frac{ 1 }{ 3 }x+\frac{ 7 }{ 3 }\]
good - next step is to substitute this into the equation of the parabola - you will end up with a quadratic involving x.
ok so... \[x ^{2}=-\frac{ 1 }{ 3 }x+\frac{ 7 }{3 }\]
and then just solve using the quadratic equation?
yes - that is correct - multiply through by 3 to remove the fractions and then solve.
\[3x^2+x-7=0\]
yup - solve to get two values for x, then use these to find the corresponding to values for y from the equation of the line you got above.
or even simpler, use \(y=x^2\) to find the corresponding values for y once you have the values for x.
\[y=(\frac{ -1\pm \sqrt{85} }{ 6 })^{2}\]
perfect! you can see a pictorial representation of this solution here: http://www.wolframalpha.com/input/?i=intersection+of+y%3Dx^2+and+3y%2Bx%3D7
Ok thanks and how do I get an exact answer from the equation I just posted? How do I square the numerator?
oh wait nvm i think i know, gimme a sec
just use a calculator :)
BTW: what you typed IS the EXACT answer. Showing it as a decimal is an approximation.
But can't what I typed be simplified?
sure - but I am /guessing/ that you are expected to write the decimal approximations of the answers.
No decimal answers, just exact... \[y=\frac{ 43 \pm \sqrt{85} }{ 18 }\]
do you want me to check that or are you confident in your work?
ya im pretty sure, thanks
yw - and well done! :)
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