Question

lim x->0 (x^2-2x+sinx/x)

How do I find the limit using:
lim x=0 sinx/x=1

Answer 1

just separate out the limits,
lim x->0 (x^2-2x+sinx/x) = lim x->0 (x^2) - lim x->0 (2x) +lim x->0 (sinx/x)
the last limit is =1
for others, just plug in x=0

Answer 2

So the answer is simply 1?

Answer 3

or was it (x^2-2x+sin x) / x ?
if its (x^2-2x+sinx/x)
then yes, limit =1