Question

Find an equation of the tangent line to the graph of the function at the point ( sqrt2/8 , pi/ 4 )
.
y = arcsec 8x

Answer 1

what is the derivative of y?

Answer 2

you need to find the slope of the tangent line, it will be given by f'(sqrt2/8)

Answer 3

derivative is 8 / abs(8x) * sqrt (64x^2 -1)

Answer 4

http://www.wolframalpha.com/input/?i=derivative+arcsec+8x

Answer 5

if that is what you got, plug in sqrt2/8 to the derivative to get the slope of the tangent line at that point

Answer 6

then you have y=mx+b and you know what m is, so use the given point to fund b

Answer 7

find b*

Answer 8

ok I will give that a try thanks!

Answer 9

for the slope i get 4 sqrt 2 but if i multiply to the x i get 1 is that right ?

Answer 10

@zzr0ck3r