Find an equation of the tangent line to the graph of the function at the point ( sqrt2/8 , pi/ 4 )
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y = arcsec 8x

Question

Find an equation of the tangent line to the graph of the function at the point ( sqrt2/8    , pi/ 4 )  
.
y = arcsec 8x

zzr0ck3r · Answer

what is the derivative of y?

anonymous · Answer

attachment

zzr0ck3r · Answer

you need to find the slope of the tangent line, it will be given by f'(sqrt2/8)

anonymous · Answer

derivative is 8 / abs(8x) * sqrt (64x^2 -1)

zzr0ck3r · Answer

zzr0ck3r · Answer

if that is what you got, plug in sqrt2/8  to the derivative to get the slope of the tangent line at that point

zzr0ck3r · Answer

then you have y=mx+b and you know what m is, so use the given point to fund b

zzr0ck3r · Answer

find b*

anonymous · Answer

ok I will give that a try thanks!

anonymous · Answer

for the slope i get 4 sqrt 2   but if i multiply to the x  i get 1  is that right ?

anonymous · Answer

@zzr0ck3r