A circle is inscribed in a square whose vertices have coordinates R(0, 4), S(6, 2), T(4, -4), and U(-2, -2). Find the equation of the circle.
A. (x - 2)² + y² = 68
B. (x + 2)² + y² = 20
C. (x - 2)² + y² = 10
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OpenStudy (mertsj):
The diameter of the circle would be the distance between two consecutive vertices and the radius is, of course, half of the diameter.
OpenStudy (mertsj):
Did you find the diameter?
OpenStudy (anonymous):
how do i find the diameter?
OpenStudy (mertsj):
Do you remember when I posted this 4 minutes ago:
The diameter of the circle would be the distance between two consecutive vertices
OpenStudy (mertsj):
Do you know the distance formula?
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OpenStudy (anonymous):
is it (x1+x2)/2?
OpenStudy (mertsj):
\[d=\sqrt{(x _{2}-x _{1})^2+(y _{2}-y _{1})^2}\]
OpenStudy (anonymous):
so would the radius be \[\sqrt{40}/2\]?
OpenStudy (mertsj):
yes. What is the radius squared?
OpenStudy (anonymous):
10?
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