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Mathematics 12 Online
OpenStudy (anonymous):

A circle is inscribed in a square whose vertices have coordinates R(0, 4), S(6, 2), T(4, -4), and U(-2, -2). Find the equation of the circle. A. (x - 2)² + y² = 68 B. (x + 2)² + y² = 20 C. (x - 2)² + y² = 10

OpenStudy (mertsj):

The diameter of the circle would be the distance between two consecutive vertices and the radius is, of course, half of the diameter.

OpenStudy (mertsj):

Did you find the diameter?

OpenStudy (anonymous):

how do i find the diameter?

OpenStudy (mertsj):

Do you remember when I posted this 4 minutes ago: The diameter of the circle would be the distance between two consecutive vertices

OpenStudy (mertsj):

Do you know the distance formula?

OpenStudy (anonymous):

is it (x1+x2)/2?

OpenStudy (mertsj):

\[d=\sqrt{(x _{2}-x _{1})^2+(y _{2}-y _{1})^2}\]

OpenStudy (anonymous):

so would the radius be \[\sqrt{40}/2\]?

OpenStudy (mertsj):

yes. What is the radius squared?

OpenStudy (anonymous):

10?

OpenStudy (mertsj):

And, in which equation is r^2=10?

OpenStudy (anonymous):

C?

OpenStudy (mertsj):

So pick C

OpenStudy (anonymous):

thank you very much

OpenStudy (mertsj):

yw

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