A circle is inscribed in a square whose vertices have coordinates R(0, 4), S(6, 2), T(4, -4), and U(-2, -2). Find the equation of the circle. A. (x - 2)² + y² = 68 B. (x + 2)² + y² = 20 C. (x - 2)² + y² = 10
The diameter of the circle would be the distance between two consecutive vertices and the radius is, of course, half of the diameter.
Did you find the diameter?
how do i find the diameter?
Do you remember when I posted this 4 minutes ago: The diameter of the circle would be the distance between two consecutive vertices
Do you know the distance formula?
is it (x1+x2)/2?
\[d=\sqrt{(x _{2}-x _{1})^2+(y _{2}-y _{1})^2}\]
so would the radius be \[\sqrt{40}/2\]?
yes. What is the radius squared?
10?
And, in which equation is r^2=10?
C?
So pick C
thank you very much
yw
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