Question

Consider the following pseudocode function.
function W(n is in Z)
if n > 0 then
if n is odd then
return 2n
else
return n + 1
else
return n − 1
Compute the values returned by the following function calls.
(a) W(14) =

(b) W(−20) =

(c) W(9) =

Answer 1

We see that if \(n\) is positive and odd we get back \(2n\); if it's even, we get back \(n+1\). If it's negative, we get back \(n-1\). Break it down now:

(a) \(n=14\) is positive and even so we get back \(W(14)=14+1=15\)
(b) \(n=-20\) is negative so we get back \(W(-20)=-20-1=-21\)
(c) \(n=9\) is positive and odd so we get back \(W(9)=2(9)=18\)

Answer 2

thank u @oldrin.bataku