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OpenStudy (anonymous):
Given f(x) = x2 + 6x and g(x) = 3x2 + 12x, find (f – g)(x).
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OpenStudy (anonymous):
here is a simple breakdown:
f(x)=(x^2 +6x)
g(x)=(3x^2 +12x)
(f-g)(x)= (f(x))-(g(x))
(f-g)(x)= (x^2 +6x)-(3x^2 +12x)
can you get it from there?
OpenStudy (anonymous):
combine like terms right?
OpenStudy (johnweldon1993):
Correct...
OpenStudy (anonymous):
4x^2+18x
OpenStudy (anonymous):
oops wait
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OpenStudy (anonymous):
2x^2+6x?
OpenStudy (johnweldon1993):
Remember first you need to distribute that '-' sign...
OpenStudy (anonymous):
oh so then it's 4x^2+13x the second part?
OpenStudy (johnweldon1993):
so you'll have
x² - 3x² = ...?
and
6x - 12x = ...?
OpenStudy (anonymous):
Just as john said, that negative sign gets distributed, then it is just a matter of combining like terms.
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OpenStudy (johnweldon1993):
So you have
(x² +6x)-(3x² +12x)
After distributing that '-' sign into the second parenthesis you have
x² + 6x - 3x² - 12x
Now combine those...
OpenStudy (anonymous):
ohh okay 2x^2-6x then
OpenStudy (johnweldon1993):
missing 1 thing still...
x² - 3x² = ...?
OpenStudy (anonymous):
-2x^2 I mean
OpenStudy (johnweldon1993):
There we go...correct -2x² - 6x
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OpenStudy (anonymous):
thanks!
OpenStudy (johnweldon1993):
No problem!
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