Question

Let f(x)=2x-7, that means that f^-1(x)=(x+7)/2.

How do you evaluate (fof^-1)(x)
and (f^-1of)(x)

Answer 1

(fof^-1)(x) is

\[f(f^{-1}(x))\]

so you plug in (f^(-1))(x) for every x in f(x):

\[f(f^{-1}(x)) = 2\frac{ x+7 }{ 2 } - 7\]

Answer 2

So, is that as far as you take it?

Answer 3

you simplify it, which gives x

Answer 4

And for the other one?